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24:[["$","$L33",null,{"feature":"flashcards"}],"$L34",["$","$L35",null,{"href":"/a-level/physics/aqa/alpha-beta-and-gamma-radiation-a-level-only/flashcards","label":"$$\\alpha$ , $\\beta$ and $\\gamma$ radiation (A-level only)","subjectCode":"a_level_physics__aqa","surface":"flashcards"}],["$","$L36",null,{"runner":["$","div",null,{"className":"min-h-0 flex-1 overflow-hidden bg-background","children":["$","$L37",null,{"decks":[{"id":"382d40a2-450b-4136-8f5a-11b71a2ddc28","title":"$$\\alpha$ , $\\beta$ and $\\gamma$ radiation (A-level only) Flashcards","topicId":"d476ebda-3026-5460-ba64-a0bc76e712e7","topicSlug":"alpha-beta-and-gamma-radiation-a-level-only","cards":[{"id":"ac9f899f-43bb-47c3-9fb7-a6088fb05395","cardType":"basic","points":1,"front":"What is background radiation?","back":"The low-level ionising radiation present in the environment at all times.","mcqOptions":[{"text":"The low-level ionising radiation present in the environment at all times.","correct":true,"explanation":"Background radiation is the continuous, low-level ionising radiation detected in the surroundings, even when no specific radioactive source has been deliberately introduced."},{"text":"The high-level ionising radiation emitted by a nearby radioactive source.","correct":false,"explanation":"Radiation from an identifiable nearby source is not background radiation. The correct definition is low-level ionising radiation that is always present in the environment."},{"text":"The low-level non-ionising radiation produced by electrical equipment.","correct":false,"explanation":"Background radiation is ionising, rather than non-ionising, and comes from natural and artificial sources. It is the low-level ionising radiation continuously present in the environment."},{"text":"The temporary ionising radiation present after a nuclear accident.","correct":false,"explanation":"A temporary increase following a nuclear event is not the general background level. Background radiation is the low-level ionising radiation present in the environment at all times."}]},{"id":"ec9f5b72-b115-43ba-b441-6af9faa11b42","cardType":"cloze","points":null,"front":"The single largest natural contributor to background radiation is [ ] released from rocks.","back":"The single largest natural contributor to background radiation is radon gas released from rocks.","mcqOptions":[{"text":"radon gas","correct":true,"explanation":"Radon is a naturally occurring radioactive gas produced in the decay chains of uranium in rocks, and it is the largest natural contributor to average background exposure."},{"text":"carbon dioxide","correct":false,"explanation":"Carbon dioxide is not radioactive under ordinary environmental conditions. The largest natural contributor is radon gas, produced by radioactive decay in rocks."},{"text":"cosmic radiation","correct":false,"explanation":"Cosmic radiation contributes to background exposure, but it is not a gas released from rocks. Radon gas is the largest natural contributor."},{"text":"gamma radiation","correct":false,"explanation":"Gamma radiation can be emitted by radioactive materials in rocks, but it is not a gas. The required contributor is radon gas."}]},{"id":"7b254fb0-eca4-4f1f-93d3-2e29df63d5dc","cardType":"cloze","points":null,"front":"The single largest natural contributor to background radiation is radon gas released from [ ].","back":"The single largest natural contributor to background radiation is radon gas released from rocks.","mcqOptions":[{"text":"rocks","correct":true,"explanation":"Radon forms in uranium decay chains within rocks and can escape through pores and cracks before accumulating in buildings and the surrounding air."},{"text":"medical scanners","correct":false,"explanation":"Medical scanners are artificial sources of exposure and do not naturally release radon. Radon is generated by radioactive decay within rocks."},{"text":"power lines","correct":false,"explanation":"Power lines produce electromagnetic fields but do not release radioactive radon gas. Radon originates from the decay of radioactive nuclei in rocks."},{"text":"nuclear reactors","correct":false,"explanation":"Nuclear reactors can contain radioactive gases, but they are not the principal natural source of radon. Environmental radon is released from rocks."}]},{"id":"89999192-0bd3-432b-8005-d1d966683e2c","cardType":"basic","points":1,"front":"How is the corrected count rate of a radioactive source calculated?","back":"$$$\\text{Measured Count Rate} - \\text{Background Count Rate}$$","mcqOptions":[{"text":"$$$\\text{Measured Count Rate} - \\text{Background Count Rate}$$","correct":true,"explanation":"The detector records radiation from both the source and the environment, so subtracting the background count rate isolates the corrected count rate due to the source."},{"text":"$$$\\text{Measured Count Rate} + \\text{Background Count Rate}$$","correct":false,"explanation":"Adding the background counts attributes environmental radiation to the source and overestimates its activity. The background count rate must be subtracted from the measured rate."},{"text":"$$$\\text{Background Count Rate} - \\text{Measured Count Rate}$$","correct":false,"explanation":"Reversing the subtraction normally produces a negative result because the measured rate includes the background. The corrected rate is measured count rate minus background count rate."},{"text":"$$$\\text{Measured Count Rate} \\div \\text{Background Count Rate}$$","correct":false,"explanation":"Division gives a ratio rather than a corrected count rate and therefore has the wrong interpretation. The environmental background must be subtracted from the measured count rate."}]},{"id":"3bbbfcfd-3e26-4a28-82f7-da661e585feb","cardType":"basic","points":2,"front":"State the composition and charge of an alpha ($\\alpha$) particle.","back":"

Helium nucleus (2 protons, 2 neutrons)
Charge of $+2e$

","mcqOptions":[{"text":"

Helium nucleus (2 protons, 2 neutrons)
Charge of $+2e$

","correct":true,"explanation":"An alpha particle is the nucleus of a helium-4 atom, containing two protons and two neutrons. Its two protons give it charge $+2e$."},{"text":"

Hydrogen nucleus (1 proton, 0 neutrons)
Charge of $+e$

","correct":false,"explanation":"A hydrogen nucleus is a proton, not an alpha particle. An alpha particle is a helium nucleus containing two protons and two neutrons, with charge $+2e$."},{"text":"

Helium atom (2 protons, 2 neutrons)
Charge of $0$

","correct":false,"explanation":"Including two electrons would make this a neutral helium atom. An alpha particle contains only the helium nucleus, so its charge is $+2e$."},{"text":"

Electron (0 protons, 0 neutrons)
Charge of $-e$

","correct":false,"explanation":"An electron is the particle emitted in beta-minus decay, not alpha decay. An alpha particle is a helium nucleus with two protons, two neutrons and charge $+2e$."}]},{"id":"6bd1daae-8ed7-482e-a6b2-928a4c5e58b5","cardType":"basic","points":2,"front":"Why does alpha radiation have a short range in air?","back":"It is highly ionising, so it loses energy rapidly through many collisions with air atoms.","mcqOptions":[{"text":"It is highly ionising, so it loses energy rapidly through many collisions with air atoms.","correct":true,"explanation":"Alpha particles have a large charge and strongly interact with matter, producing many ionisations. These interactions rapidly remove their kinetic energy, limiting their range in air."},{"text":"It is weakly ionising, so it loses energy rapidly through many collisions with air atoms.","correct":false,"explanation":"Weak ionisation would generally allow radiation to travel farther before losing its energy. Alpha radiation has a short range because it is highly ionising."},{"text":"It is electrically neutral, so it loses energy rapidly through many collisions with air atoms.","correct":false,"explanation":"Alpha particles carry charge $+2e$ rather than being uncharged. This large charge causes strong interactions and rapid energy loss through ionisation."},{"text":"It is travelling at light speed, so it loses energy rapidly through many collisions with air atoms.","correct":false,"explanation":"Alpha particles do not travel at the speed of light, and greater speed does not explain their short range. Their high ionising ability causes rapid energy loss."}]},{"id":"7efd841b-b5ce-4fa2-91cb-22342c4b41e7","cardType":"cloze","points":null,"front":"While alpha radiation travels only a few centimetres in air, [ ] radiation travels about 1 metre.","back":"While alpha radiation travels only a few centimetres in air, beta ($\\beta$) radiation travels about 1 metre.","mcqOptions":[{"text":"beta ($\\beta$)","correct":true,"explanation":"Beta particles are less strongly ionising than alpha particles, so they lose energy less rapidly and typically travel around one metre through air."},{"text":"gamma ($\\gamma$)","correct":false,"explanation":"Gamma radiation is much more penetrating than beta radiation and typically travels far beyond one metre in air. The stated intermediate range belongs to beta radiation."},{"text":"neutron ($n$)","correct":false,"explanation":"Neutron radiation does not have the characteristic approximate one-metre range used in this comparison. Beta radiation has the intermediate penetration described."},{"text":"X-ray ($X$)","correct":false,"explanation":"X-rays are penetrating electromagnetic radiation and are not normally assigned this approximate one-metre range. The radiation described is beta radiation."}]},{"id":"00471a6a-613e-408a-9898-039ea27924a3","cardType":"cloze","points":null,"front":"While alpha radiation travels only a few centimetres in air, beta ($\\beta$) radiation travels about [ ].","back":"While alpha radiation travels only a few centimetres in air, beta ($\\beta$) radiation travels about 1 metre.","mcqOptions":[{"text":"1 metre","correct":true,"explanation":"Beta particles are moderately ionising and therefore have an intermediate range, typically around one metre in air, compared with alpha’s few centimetres."},{"text":"5 centimetres","correct":false,"explanation":"This confuses beta’s range with the much shorter range of alpha radiation. Beta is less ionising and typically travels about 1 metre through air."},{"text":"100 metres","correct":false,"explanation":"This greatly overestimates beta penetration and is more suggestive of highly penetrating electromagnetic radiation. Beta radiation typically travels about 1 metre in air."},{"text":"1 millimetre","correct":false,"explanation":"This is closer to beta’s penetration through solid absorbers than its range in air. In air, beta radiation typically travels about 1 metre."}]},{"id":"cca667a0-9301-41de-84d6-0ce5935acb1a","cardType":"basic","points":2,"front":"Explain the general relationship between ionising power and penetrating power.","back":"They are inversely related: high ionising power causes energy loss, resulting in low penetration.","mcqOptions":[{"text":"They are inversely related: high ionising power causes energy loss, resulting in low penetration.","correct":true,"explanation":"Ionising radiation loses energy as it creates ions. More ionising radiation deposits energy over a shorter distance, so it has lower penetrating power."},{"text":"They are directly related: high ionising power causes energy gain, resulting in high penetration.","correct":false,"explanation":"A direct relationship confuses ionisation with intensity. Frequent ionising collisions drain energy quickly, so the correct relationship is inverse: high ionising power gives low penetration."},{"text":"They are directly related: high ionising power causes energy loss, resulting in high penetration.","correct":false,"explanation":"Energy loss does not help radiation travel further. If radiation loses energy rapidly through ionisation, it is absorbed sooner, so high ionising power means low penetration."},{"text":"They are unrelated properties: high ionising power has no effect, resulting in variable penetration.","correct":false,"explanation":"The properties are linked by energy transfer to atoms. More ionising interactions mean faster energy loss in the material, so ionising power and penetrating power are inversely related."}]},{"id":"fd64a0b3-efe6-40b5-8fcf-ad49026c1f3c","cardType":"basic","points":1,"front":"Which material is required to significantly reduce the count rate of beta ($\\beta$) radiation?","back":"A few millimetres of aluminium.","mcqOptions":[{"text":"A few millimetres of aluminium.","correct":true,"explanation":"Beta particles have moderate penetrating power and are significantly absorbed by a few millimetres of aluminium, which is the standard shielding material for beta radiation."},{"text":"A few millimetres of paper.","correct":false,"explanation":"Paper is enough to stop alpha radiation, not beta radiation. Beta particles are more penetrating, so a few millimetres of aluminium is needed to reduce the count rate significantly."},{"text":"A few millimetres of air.","correct":false,"explanation":"A few millimetres of air is far too little because beta particles can travel much further in air. The expected absorber is a few millimetres of aluminium."},{"text":"A few millimetres of skin.","correct":false,"explanation":"Skin is associated with stopping alpha radiation and some very low-energy beta, but it is not the standard absorber. A few millimetres of aluminium significantly reduces beta count rate."}]},{"id":"a27c00f4-c58b-42da-b61a-2134f588e101","cardType":"basic","points":2,"front":"Why is gamma ($\\gamma$) radiation considered weakly ionising?","back":"It has no mass and no charge (it is a photon), making interactions with atoms less frequent.","mcqOptions":[{"text":"It has no mass and no charge (it is a photon), making interactions with atoms less frequent.","correct":true,"explanation":"Gamma radiation consists of photons with no charge and no rest mass, so it interacts with atoms less often than charged particles such as alpha or beta radiation."},{"text":"It has large mass and positive charge (it is a helium nucleus), making interactions with atoms more frequent.","correct":false,"explanation":"That describes alpha radiation, which is strongly ionising because it is massive and charged. Gamma is weakly ionising because it has no mass and no charge."},{"text":"It has small mass and negative charge (it is an electron), making interactions with atoms less frequent.","correct":false,"explanation":"That describes beta radiation, which is still charged and therefore ionises more readily than gamma. Gamma is weakly ionising because photons have no mass and no charge."},{"text":"It has high mass and no charge (it is a neutron), making interactions with atoms less frequent.","correct":false,"explanation":"Gamma radiation is not a neutron and has no rest mass. Its weak ionisation comes from being an uncharged photon, so interactions with atoms are relatively infrequent."}]},{"id":"a8206926-fd5c-4f58-a8b7-fe2bfb941d90","cardType":"basic","points":3,"front":"In thickness monitoring of paper, why is a beta source used instead of alpha or gamma?","back":"

Alpha is stopped entirely by paper
Gamma passes through with no measurable change
Beta count rate varies with thickness

","mcqOptions":[{"text":"

Alpha is stopped entirely by paper
Gamma passes through with no measurable change
Beta count rate varies with thickness

","correct":true,"explanation":"Paper absorbs alpha too strongly and gamma too weakly for useful monitoring. Beta has intermediate penetration, so changes in paper thickness produce measurable count-rate changes."},{"text":"

Alpha passes through with no measurable change
Gamma is stopped entirely by paper
Beta count rate is unaffected by thickness

","correct":false,"explanation":"This reverses the penetrating powers. Alpha is stopped by paper, gamma mostly passes through, and beta is chosen because its count rate changes measurably with thickness."},{"text":"

Alpha count rate varies with thickness
Gamma is stopped entirely by paper
Beta passes through with no measurable change

","correct":false,"explanation":"This treats alpha as if it had beta’s moderate penetration and gamma as if it were easily stopped. In paper monitoring, beta gives the useful thickness-dependent count rate."},{"text":"

Alpha is stopped entirely by paper
Gamma count rate varies with thickness
Beta passes through with no measurable change

","correct":false,"explanation":"Alpha being stopped by paper is correct, but gamma is too penetrating to change enough in paper. Beta, not gamma, gives a count rate that varies with thickness."}]},{"id":"3c8bdb0b-e7fb-4a8a-ae24-9d9f4673142f","cardType":"cloze","points":null,"front":"In the thickness monitoring of steel sheets, a [ ] source must be used because alpha and beta would be completely absorbed.","back":"In the thickness monitoring of steel sheets, a gamma ($\\gamma$) source must be used because alpha and beta would be completely absorbed.","mcqOptions":[{"text":"gamma ($\\gamma$)","correct":true,"explanation":"Steel sheets are too thick and dense for alpha or beta radiation to pass through usefully. Gamma’s high penetrating power allows a measurable transmitted count rate."},{"text":"beta ($\\beta$)","correct":false,"explanation":"Beta is suitable for thinner materials such as paper or very thin foil, but steel would absorb it almost completely. Gamma radiation is needed for steel thickness monitoring."},{"text":"proton","correct":false,"explanation":"Protons are charged particles, so they ionise strongly and have poor penetration in dense materials. A gamma source is used because it can pass through steel sheets."},{"text":"visible light","correct":false,"explanation":"Steel is opaque to visible light, so it would not provide a transmitted count rate for thickness monitoring. Gamma radiation is required because it can penetrate steel."}]},{"id":"a14e480f-42bf-4baf-ab43-dc3019dcd4a2","cardType":"cloze","points":null,"front":"In the thickness monitoring of steel sheets, a gamma ($\\gamma$) source must be used because alpha and beta would be [ ].","back":"In the thickness monitoring of steel sheets, a gamma ($\\gamma$) source must be used because alpha and beta would be completely absorbed.","mcqOptions":[{"text":"completely absorbed","correct":true,"explanation":"Alpha and beta radiation have much lower penetrating power than gamma. In steel sheets they would be absorbed before reaching the detector, so gamma must be used."},{"text":"partly transmitted","correct":false,"explanation":"Partly transmitted is the useful behaviour of gamma radiation in this application, not alpha or beta. Alpha and beta would be completely absorbed by steel."},{"text":"weakly ionising","correct":false,"explanation":"This confuses ionising power with penetration. Alpha is strongly ionising and beta is moderately ionising, but the key point is that both would be completely absorbed by steel."},{"text":"highly penetrating","correct":false,"explanation":"Alpha and beta are not penetrating enough to pass through steel sheets. Gamma is the highly penetrating radiation, while alpha and beta would be completely absorbed."}]},{"id":"8eea10f2-b851-4747-96e9-7ef33527c60c","cardType":"basic","points":2,"front":"Why is alpha radiation the most hazardous when inside the body (contamination)?","back":"Its high ionising power causes massive cellular damage and DNA mutation in a very localized area.","mcqOptions":[{"text":"Its high ionising power causes massive cellular damage and DNA mutation in a very localized area.","correct":true,"explanation":"Inside the body, alpha radiation is no longer blocked by skin. Its very high ionising power deposits energy in nearby tissue, causing severe cellular damage and DNA mutation locally."},{"text":"Its high penetrating power causes massive cellular damage and DNA mutation in a very localized area.","correct":false,"explanation":"Alpha is not highly penetrating; it is dangerous internally because it is highly ionising. It deposits energy over a short range, causing massive cellular damage and DNA mutation."},{"text":"Its high ionising power causes minor cellular damage and DNA repair in a very localized area.","correct":false,"explanation":"High ionising power does not cause minor damage or DNA repair. Internally, alpha radiation can cause massive cellular damage and DNA mutation in a very localized region."},{"text":"Its low ionising power causes massive cellular damage and DNA mutation throughout the whole body.","correct":false,"explanation":"Alpha radiation has high, not low, ionising power, and its range is short rather than body-wide. The hazard is severe localized cellular damage and DNA mutation."}]},{"id":"4ac8279b-6d30-4f52-bbb3-d2bb7c946090","cardType":"basic","points":2,"front":"Why is gamma radiation more hazardous than alpha when outside the body (irradiation)?","back":"Gamma is highly penetrating and can reach internal organs, whereas alpha is stopped by dead skin cells.","mcqOptions":[{"text":"Gamma is highly penetrating and can reach internal organs, whereas alpha is stopped by dead skin cells.","correct":true,"explanation":"Outside the body, alpha radiation is blocked by the outer dead skin layer. Gamma radiation penetrates much further, so it can reach and irradiate internal organs."},{"text":"Gamma is weakly penetrating and cannot reach internal organs, whereas alpha passes through dead skin cells.","correct":false,"explanation":"This reverses the external hazard. Gamma is highly penetrating and can reach internal organs, while alpha is stopped by dead skin cells."},{"text":"Gamma is highly ionising and is stopped by dead skin cells, whereas alpha can reach internal organs.","correct":false,"explanation":"Gamma is weakly ionising but highly penetrating, and it is not stopped by dead skin cells. Alpha is the radiation stopped by skin, so gamma is the greater external hazard."},{"text":"Gamma is low energy and can only damage skin, whereas alpha passes through to internal organs.","correct":false,"explanation":"The misconception is treating alpha as the more penetrating radiation. In external irradiation, gamma can penetrate to internal organs, while alpha is stopped by dead skin cells."}]},{"id":"bf3f7509-7df0-4120-8665-5ecdc57535d6","cardType":"basic","points":1,"front":"State the inverse-square law for gamma radiation intensity ($I$) at distance ($x$).","back":"$$$I = \\frac{k}{x^2}$$","mcqOptions":[{"text":"$$$I = \\frac{k}{x^2}$$","correct":true,"explanation":"Radiation from a point source spreads over a spherical area proportional to $x^2$, so its intensity is inversely proportional to the square of the distance."},{"text":"$$$I = \\frac{k}{x}$$","correct":false,"explanation":"This treats intensity as inversely proportional to distance rather than spherical area. The spreading area increases as $x^2$, so the correct relationship is $I = \\frac{k}{x^2}$."},{"text":"$$$I = \\frac{k}{2x}$$","correct":false,"explanation":"Dividing by twice the distance does not describe three-dimensional spreading. Gamma radiation from a point source obeys $I = \\frac{k}{x^2}$ because spherical area grows with $x^2$."},{"text":"$$$I = kx^2$$","correct":false,"explanation":"This incorrectly predicts that intensity increases with distance. Radiation becomes more spread out as distance increases, giving the inverse-square relationship $I = \\frac{k}{x^2}$."}]},{"id":"f3b43a27-35f4-4e1c-96c3-1eaf9323d89d","cardType":"cloze","points":null,"front":"If the distance from a point gamma source is tripled, the intensity of the radiation decreases by a factor of [ ].","back":"If the distance from a point gamma source is tripled, the intensity of the radiation decreases by a factor of 9.","mcqOptions":[{"text":"9","correct":true,"explanation":"Intensity is proportional to $1/x^2$, so tripling the distance changes the intensity by a factor of $1/3^2 = 1/9$. It therefore decreases by a factor of 9."},{"text":"3","correct":false,"explanation":"A factor of 3 follows an inverse-distance relationship, not an inverse-square relationship. Squaring the tripled distance gives $3^2 = 9$, so intensity decreases by a factor of 9."},{"text":"6","correct":false,"explanation":"Multiplying the distance factor by the power gives 6, but the distance must instead be squared. Therefore, tripling distance reduces intensity by a factor of $3^2 = 9$."},{"text":"27","correct":false,"explanation":"A factor of 27 comes from cubing the distance, as in an inverse-cube relationship. Gamma intensity follows an inverse-square law, so the decrease is by a factor of 9."}]},{"id":"d5a9d294-171a-4bc7-a3c1-452e70c8e557","cardType":"basic","points":2,"front":"How is the inverse-square law verified graphically using count rate ($I$) and distance ($x$)?","back":"Plot a graph of $I$ against $1/x^2$; it should be a straight line through the origin.","mcqOptions":[{"text":"Plot a graph of $I$ against $1/x^2$; it should be a straight line through the origin.","correct":true,"explanation":"The relationship $I = k(1/x^2)$ has the form $y = mx$, so plotting $I$ against $1/x^2$ should produce a straight line through the origin."},{"text":"Plot a graph of $I$ against $x^2$; it should be a straight line through the origin.","correct":false,"explanation":"Intensity is not directly proportional to $x^2$; it is inversely proportional to it. A straight-line test therefore requires $I$ to be plotted against $1/x^2$."},{"text":"Plot a graph of $I$ against $1/x$; it should be a straight line through the origin.","correct":false,"explanation":"This tests an inverse-distance law rather than an inverse-square law. Since $I \\propto 1/x^2$, the horizontal axis must be $1/x^2$ for a straight line."},{"text":"Plot a graph of $I$ against $1/x^2$; it should be a curve approaching the origin.","correct":false,"explanation":"Although $I$ against $x$ is curved, transforming the horizontal variable to $1/x^2$ linearises the relationship. The expected graph is a straight line through the origin."}]},{"id":"2b9c6127-8c8c-48cd-809b-4c406f012979","cardType":"basic","points":2,"front":"What does it indicate if an $I$ vs. $1/x^2$ graph is linear but does not pass through the origin?","back":"There is a systematic error in the distance measurement (e.g., source depth within the casing).","mcqOptions":[{"text":"There is a systematic error in the distance measurement (e.g., source depth within the casing).","correct":true,"explanation":"A consistent offset between the measured distance and the true distance from the source produces a systematic error, such as measuring from the casing rather than the source itself."},{"text":"There is a random error in each count-rate measurement (e.g., unpredictable nuclear decay).","correct":false,"explanation":"Random decay fluctuations scatter points around a trend rather than producing a consistent failure to pass through the origin. The stated pattern indicates a systematic distance error, such as unaccounted source depth."},{"text":"There is a change in activity during the experiment (e.g., rapid source decay between readings).","correct":false,"explanation":"A changing source activity would make measurements depend on when they were taken and would not normally preserve the stated linear pattern. A systematic distance offset explains the non-zero intercept."},{"text":"There is a failure of the inverse-square law at all measured distances (e.g., intensity proportional to $1/x$).","correct":false,"explanation":"A different power law would generally make $I$ against $1/x^2$ non-linear. Linearity supports the inverse-square relationship, while the missed origin points to a systematic distance error."}]},{"id":"f1389897-11df-485b-83a4-af53825ca0b0","cardType":"cloze","points":null,"front":"Medical tracers often use gamma sources because they [ ] to be detected and have short half-lives to minimize risk.","back":"Medical tracers often use gamma sources because they penetrate out of the body to be detected and have short half-lives to minimize risk.","mcqOptions":[{"text":"penetrate out of the body","correct":true,"explanation":"Gamma photons are sufficiently penetrating to leave the patient's body and reach an external detector, allowing the tracer's location and movement to be monitored without surgery."},{"text":"are completely absorbed by the body","correct":false,"explanation":"Complete absorption would prevent radiation from reaching an external detector. Gamma sources are suitable because their radiation can penetrate out of the body and be detected externally."},{"text":"produce a strong electric current","correct":false,"explanation":"Medical tracers are located by detecting emitted gamma photons, not by measuring an electric current from the source. Gamma radiation is used because it penetrates out of the body."},{"text":"remain confined within the organ","correct":false,"explanation":"If the radiation remained confined, an external detector could not locate the tracer. The gamma photons must penetrate out of the body so that they can be detected."}]},{"id":"60ba2da0-b3b7-4a98-b132-35438b9b001a","cardType":"cloze","points":null,"front":"Medical tracers often use gamma sources because they penetrate out of the body to be detected and have [ ] to minimize risk.","back":"Medical tracers often use gamma sources because they penetrate out of the body to be detected and have short half-lives to minimize risk.","mcqOptions":[{"text":"short half-lives","correct":true,"explanation":"A short half-life allows sufficient activity while the tracer is being monitored but ensures that the activity falls quickly afterwards, limiting the patient's total radiation dose."},{"text":"long half-lives","correct":false,"explanation":"A long half-life would leave the tracer radioactive inside the patient for longer and increase exposure. Medical tracers instead use short half-lives to minimise the total dose."},{"text":"high ionising powers","correct":false,"explanation":"Highly ionising radiation deposits more energy in tissue and increases biological damage. Medical tracers need detectable gamma emission and short half-lives, not high ionising power."},{"text":"long biological lifetimes","correct":false,"explanation":"Remaining in the body for a long time would prolong internal exposure. Tracers are chosen to have short half-lives so their activity decreases quickly after the investigation."}]},{"id":"948fb92a-4004-4c88-819d-f058d7908555","cardType":"basic","points":2,"front":"Why is the use of long-handled tongs an effective safety measure for radioactive sources?","back":"Increasing distance dramatically reduces intensity reaching the user, following the inverse-square law.","mcqOptions":[{"text":"Increasing distance dramatically reduces intensity reaching the user, following the inverse-square law.","correct":true,"explanation":"Long-handled tongs increase the user's distance from the source. Since intensity is proportional to $1/x^2$, even a modest distance increase substantially reduces exposure."},{"text":"Increasing distance completely absorbs radiation before it reaches the user, following the shielding principle.","correct":false,"explanation":"Distance does not completely absorb gamma radiation, and tongs are not primarily shielding. They reduce exposure by increasing distance, causing intensity to fall according to the inverse-square law."},{"text":"Increasing handling time dramatically reduces activity before it reaches the user, following the half-life law.","correct":false,"explanation":"Tongs do not rely on the source decaying during handling, and increasing handling time would raise the dose. Their benefit comes from increasing distance under the inverse-square law."},{"text":"Increasing distance dramatically reduces ionisation within the source, following the decay law.","correct":false,"explanation":"Moving the user farther away does not change the source's activity or decay process. It reduces the intensity reaching the user because radiation spreads out according to the inverse-square law."}]},{"id":"417d83be-9de9-4471-949a-22d86110bc48","cardType":"basic","points":2,"front":"Why does the inverse-square law not strictly apply to alpha or beta radiation in air?","back":"Unlike gamma, alpha and beta are absorbed by air atoms, causing the count rate to drop faster than $1/x^2$.","mcqOptions":[{"text":"Unlike gamma, alpha and beta are absorbed by air atoms, causing the count rate to drop faster than $1/x^2$.","correct":true,"explanation":"Alpha and beta particles lose energy through interactions with air and can be absorbed before reaching the detector. Their count rates therefore fall faster than geometric spreading alone predicts."},{"text":"Unlike gamma, alpha and beta are unaffected by air atoms, causing the count rate to remain constant with $x$.","correct":false,"explanation":"Charged alpha and beta particles interact strongly with air rather than travelling unaffected. Absorption adds to geometric spreading, so their count rates decrease faster than $1/x^2$."},{"text":"Unlike gamma, alpha and beta are accelerated by air atoms, causing the count rate to rise faster than $x^2$.","correct":false,"explanation":"Collisions with air make alpha and beta particles lose energy; they do not accelerate them or increase the count rate. Absorption causes the measured rate to fall faster than $1/x^2$."},{"text":"Unlike gamma, alpha and beta are reflected by air atoms, causing the count rate to fall exactly as $1/x^2$.","correct":false,"explanation":"The main additional effect is energy loss and absorption, not reflection. Because some particles are stopped by air, their count rate falls more rapidly than the inverse-square prediction."}]}]}],"examCountdown":{"examDate":"2027-05-21","paperLabel":"Paper 1"},"heading":"$$\\alpha$ , $\\beta$ and $\\gamma$ radiation (A-level only)","title":"$$\\alpha$ , $\\beta$ and $\\gamma$ radiation (A-level only) Flashcards","topbar":{"backHref":"/a-level/physics/aqa/flashcards"},"topicSidebar":"$L38"}]}],"topicId":"d476ebda-3026-5460-ba64-a0bc76e712e7","walled":"$L39"}],"$L3a","$L3b"]

α, β and γ radiation (A-level only) Flashcards

α, β and γ radiation (A-level only) Flashcards