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A particular species of orchid is being studied. The population p p\,p at time t t\,t years after the study started is assumed to be

p=2800ae0.2t1+ae0.2t, where a is a constant. p = \frac{2800ae^{0.2t}}{1 + ae^{0.2t}}, \text{ where } a \text{ is a constant.} p=1+ae0.2t2800ae0.2t​, where a is a constant.
a.

Given that there were 300 orchids when the study started, show that a=0.12a = 0.12a=0.12.

[3]
b.

Use the equation with a=0.12a = 0.12a=0.12 to predict the number of years before the population of orchids reaches 1850.

[4]
c.

Show that p=3360.12+e−0.2t\displaystyle p = \frac{336}{0.12 + e^{-0.2t}}p=0.12+e−0.2t336​.

[1]
d.

Hence show that the population cannot exceed 2800.

[2]

Logs Questions

Practise Edexcel A Level Old Maths Logs with exam-style questions for A Level Old Maths. 16 questions, matched to the Edexcel A Level Old Maths (9371) specification and written in Unit exams C1, C2, C3 and C4 plus two applied units (e.g. S1 and M1) style. Every question includes a full worked solution and mark scheme, so you can see where marks are awarded rather than just whether you got the answer right.

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