Three forces F1\mathbf{F}_1F1, F2\mathbf{F}_2F2 and F3\mathbf{F}_3F3 act on a particle of mass 2 kg.
It is given that F1=(3i+4j)\mathbf{F}_1 = (3\mathbf{i} + 4\mathbf{j})F1=(3i+4j) N, F2=(ki−2j)\mathbf{F}_2 = (k\mathbf{i} - 2\mathbf{j})F2=(ki−2j) N and F3=(−5i+6j)\mathbf{F}_3 = (-5\mathbf{i} + 6\mathbf{j})F3=(−5i+6j) N, where k k\,k is a constant.
The acceleration of the particle is in the direction of the vector i+2j\mathbf{i} + 2\mathbf{j}i+2j.
Find the value of kkk.
Find the exact magnitude of the acceleration of the particle.