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2 Unit 2: Applied Mathematics A

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Question 103

In this question use g=9.8g = 9.8g=9.8 m s−2^{-2}−2

A man of mass 70 kg stands on the floor of a lift.

The lift is moving vertically upwards with acceleration 1.5 m s−2^{-2}−2.

a.

Find the magnitude of the normal reaction force exerted by the floor of the lift on the man.

[3]
b.

State the magnitude and direction of the force exerted by the man on the floor of the lift, giving a reason for your answer.

[2]
Markscheme

2 Unit 2: Applied Mathematics A Questions

  1. A Level
  2. /Maths
  3. /2 Unit 2: Applied Mathematics A

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