In this question use g=9.8g = 9.8g=9.8 m s−2^{-2}−2
A particle of mass 5 kg rests on a smooth horizontal floor.
A force of magnitude P P\,P newtons is applied to the particle, acting vertically upwards.
Given that P=20P = 20P=20, find the magnitude of the normal reaction of the floor on the particle.
Find the value of P P\,P for which the particle is on the point of leaving the floor.
Given instead that P=69P = 69P=69, find the magnitude and direction of the acceleration of the particle.