Determine the values of x x\,x in the interval 0<x<π 0 < x < \pi\,0<x<π that satisfy the equation:
(3x−7.5)(3cosecx−2)=0 (3x - 7.5)(\sqrt{3}\operatorname{cosec} x - 2) = 0 (3x−7.5)(3cosecx−2)=0Solve, for 0∘<θ<360∘0^\circ < \theta < 360^\circ0∘<θ<360∘, the equation:
3cos2θ+8cosθ=1 3\cos 2\theta + 8\cos \theta = 1 3cos2θ+8cosθ=1Give your answers to one decimal place.
97 exam-style questions on WJEC A Level Maths 1.5 Trigonometry, covering 1.5.1 Trigonometry, 1.5.2 Trigonometry, 1.5.3 Trigonometry, 1.5.4 Trigonometry, and 1.5.5 Trigonometry. Each one has a worked solution and a mark scheme showing where the marks go.