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1.5 Trigonometry

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Question 21

In the triangle ABCABCABC, AB=(x+3)cmAB = (x + 3)\text{cm}AB=(x+3)cm, BC=(x+2)cmBC = (x + 2)\text{cm}BC=(x+2)cm, AC=xcmAC = x\text{cm}AC=xcm and angle BAC=60∘BAC = 60^\circBAC=60∘

Find the value of xxx.

[5]

1.5 Trigonometry Questions

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