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1.5.5 Trigonometry

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Question 10

Solve, for −180°⩽θ<180°-180° \leqslant \theta < 180°−180°⩽θ<180°, the equation tan⁡(θ+30°)=−2.5\tan(\theta + 30°) = -2.5tan(θ+30°)=−2.5

Give your answers to 1 decimal place.

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Markscheme

1.5.5 Trigonometry Questions

  1. A Level
  2. /Maths
  3. /1.5.5 Trigonometry

42 exam-style questions on WJEC A Level Maths 1.5.5 Trigonometry. Each one has a worked solution and a mark scheme showing where the marks go.

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