Solve, for −180°⩽θ<180°-180° \leqslant \theta < 180°−180°⩽θ<180°, the equation tan(θ+30°)=−2.5\tan(\theta + 30°) = -2.5tan(θ+30°)=−2.5
Give your answers to 1 decimal place.
42 exam-style questions on WJEC A Level Maths 1.5.5 Trigonometry. Each one has a worked solution and a mark scheme showing where the marks go.