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In a right-angled triangle, [...]\text{[...]}[...], cos⁡θ=adjacenthypotenuse\cos\theta=\frac{\text{adjacent}}{\text{hypotenuse}}cosθ=hypotenuseadjacent​ and tan⁡θ=oppositeadjacent\tan\theta=\frac{\text{opposite}}{\text{adjacent}}tanθ=adjacentopposite​.

A

Upwards from a horizontal line.

B

248∘248^\circ248∘

C

It produces a horizontal phase shift.

D

In a right-angled triangle, sin⁡θ=oppositehypotenuse\boxed{\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}}sinθ=hypotenuseopposite​​, cos⁡θ=adjacenthypotenuse\cos\theta=\frac{\text{adjacent}}{\text{hypotenuse}}cosθ=hypotenuseadjacent​ and tan⁡θ=oppositeadjacent\tan\theta=\frac{\text{opposite}}{\text{adjacent}}tanθ=adjacentopposite​.

Card 1 of 23

4.4 Trigonometry (A-level only) Flashcards

  1. A Level
  2. /Maths
  3. /4.4 Trigonometry (A-level only)

23 flashcards on WJEC A Level Maths 4.4 Trigonometry (A-level only): the key formulae, methods and definitions you need to recall for AS Unit 1, AS Unit 2, A2 Unit 3 and A2 Unit 4.

Flashcards