An arithmetic sequence has first term a a\,a and common difference ddd. The sum of the first 25 terms of the sequence is equal to the square of the sum of the first 10 terms.
Show that 4a2+36ad+81d2=a+12d4a^2 + 36ad + 81d^2 = a + 12d4a2+36ad+81d2=a+12d.
Given that the 10th term of the sequence is 2, find the possible values of aaa.
231 exam-style questions on WJEC A Level Maths 3.4 Sequences and Series (A-level only), covering 3.4.1 Sequences and Series (A-level only), 3.4.2 Sequences and Series (A-level only), 3.4.3 Sequences and Series (A-level only), 3.4.4 Sequences and Series (A-level only), 3.4.5 Sequences and Series (A-level only), 3.4.6 Sequences and Series (A-level only), and 3.4.7 Sequences and Series (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.