Given that P(X)=xP(X) = xP(X)=x and P(Y)=yP(Y) = yP(Y)=y, express P(X∪Y)P(X \cup Y)P(X∪Y) in terms of xxx and yyy when: (i) XXX and YYY are mutually exclusive, (ii) XXX and YYY are independent.
Two events CCC and DDD are such that
P(C∩D′)=0.25,P(D)=0.40andP(C∣D)=0.2 P(C \cap D') = 0.25, \quad P(D) = 0.40 \quad \text{and} \quad P(C|D) = 0.2 P(C∩D′)=0.25,P(D)=0.40andP(C∣D)=0.2Find the value of: P(C∪D)P(C \cup D)P(C∪D)
P(C∩D)P(C \cap D)P(C∩D)
P(C)P(C)P(C)
111 exam-style questions on WJEC A Level Maths 4.1.1 Probability (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.