f(x)=ln(x+4)−x+1f(x) = \ln(x+4) - x + 1f(x)=ln(x+4)−x+1
Show that the equation f(x)=0f(x) = 0f(x)=0 can be written in the form x=ln(x+4)+1x = \ln(x+4) + 1x=ln(x+4)+1
Use the iteration formula xn+1=ln(xn+4)+1x_{n+1} = \ln(x_n + 4) + 1xn+1=ln(xn+4)+1 with x0=2.5x_0 = 2.5x0=2.5 to find, to 3 decimal places, the values of x1x_1x1, x2 x_2\,x2 and x3x_3x3.
By choosing a suitable interval, prove that α=2.937\alpha = 2.937α=2.937 to 3 decimal places.
