ards","topicId":"aae14ef5-498e-4e06-b367-6b59a8654733","topicSlug":"kinematics-9","cards":[{"id":"5298d04d-245d-4deb-955e-3934b19037aa","cardType":"basic","front":"What is the projectile's acceleration when air resistance is ignored and upwards is positive?","back":"$\\mathbf{a}=-g\\mathbf{j}$","points":1,"mcqOptions":null},{"id":"8a881796-2d8e-49fa-b1d2-949f160a95e1","cardType":"basic","front":"Why can horizontal and vertical projectile motion be considered separately?","back":"Gravity has no horizontal component.","points":2,"mcqOptions":null},{"id":"98d21abd-edd7-49c8-9cac-c6fa8a892337","cardType":"cloze","front":"For horizontal projectile motion, $\\text{[...]}$ and $x=u\\cos\\theta\\,t$.","back":"For horizontal projectile motion, $\\boxed{v_x=u\\cos\\theta}$ and $x=u\\cos\\theta\\,t$.","points":null,"mcqOptions":null},{"id":"9a06be69-9be3-4bc2-ad08-1dc4524b0c1e","cardType":"cloze","front":"For horizontal projectile motion, $v_x=u\\cos\\theta$ and $\\text{[...]}$.","back":"For horizontal projectile motion, $v_x=u\\cos\\theta$ and $\\boxed{x=u\\cos\\theta\\,t}$.","points":null,"mcqOptions":null},{"id":"1b3984a2-bde7-4a83-aad9-ab74ed12f143","cardType":"cloze","front":"For vertical projectile motion, $\\text{[...]}$ and $y=u\\sin\\theta\\,t-\\frac{1}{2}gt^2$.","back":"For vertical projectile motion, $\\boxed{v_y=u\\sin\\theta-gt}$ and $y=u\\sin\\theta\\,t-\\frac{1}{2}gt^2$.","points":null,"mcqOptions":null},{"id":"b34c7874-26af-4c16-a7f0-e76660eb3835","cardType":"cloze","front":"For vertical projectile motion, $v_y=u\\sin\\theta-gt$ and $\\text{[...]}$.","back":"For vertical projectile motion, $v_y=u\\sin\\theta-gt$ and $\\boxed{y=u\\sin\\theta\\,t-\\frac{1}{2}gt^2}$.","points":null,"mcqOptions":null},{"id":"7cf5253a-1941-4f84-b105-066458b7578d","cardType":"basic","front":"How is a projectile's speed found from its velocity components?","back":"$|\\mathbf{v}|=\\sqrt{v_x^2+v_y^2}$","points":1,"mcqOptions":null},{"id":"dd721a93-043a-4c3d-8379-f2f97a15bd12","cardType":"basic","front":"What is the projectile's speed at time $t$?","back":"$\\sqrt{u^2\\cos^2\\theta+(u\\sin\\theta-gt)^2}$","points":1,"mcqOptions":null},{"id":"464340c4-0f9a-4cc5-8cd3-95b30913273c","cardType":"basic","front":"How is the direction $\\alpha$ from the positive horizontal found at time $t$?","back":"$\\tan\\alpha=\\dfrac{u\\sin\\theta-gt}{u\\cos\\theta}$","points":1,"mcqOptions":null},{"id":"6f9a795e-4ca7-4ea8-b1bc-f1f01526d1e2","cardType":"basic","front":"What indicates whether a projectile is ascending or descending?","back":"The sign of $v_y$: positive ascending, negative descending.","points":1,"mcqOptions":null},{"id":"e7ffdc97-4bbb-4392-b691-d6ffa2e0373b","cardType":"basic","front":"What velocity condition holds at the greatest height?","back":"The vertical velocity is $v_y=0$.","points":1,"mcqOptions":null},{"id":"42d1d790-dcb2-428a-acc1-ebd7f6823160","cardType":"basic","front":"When does a projectile reach its greatest height?","back":"$t_{\\text{top}}=\\dfrac{u\\sin\\theta}{g}$","points":1,"mcqOptions":null},{"id":"14a558a1-4784-4ab2-9004-8e644b929265","cardType":"basic","front":"What is the time of flight when launch and landing heights are equal?","back":"$T=\\dfrac{2u\\sin\\theta}{g}$","points":1,"mcqOptions":null},{"id":"62ff113c-5771-4aa2-9bd1-dc1fff2f7b16","cardType":"basic","front":"How is flight time found when the landing height differs from the launch height?","back":"Substitute the landing height into the vertical displacement equation and solve the quadratic.","points":2,"mcqOptions":null},{"id":"f156f84d-2c79-4b08-9b5c-32ae03fb915d","cardType":"basic","front":"What is the greatest height above the point of projection?","back":"$H=\\dfrac{u^2\\sin^2\\theta}{2g}$","points":1,"mcqOptions":null},{"id":"22900406-0638-4a23-b06b-3e73003caf3b","cardType":"basic","front":"What is the horizontal range on level ground?","back":"$R=\\dfrac{u^2\\sin

4.8.3 Kinematics (A-level only) Flashcards

4.8.3 Kinematics (A-level only) Flashcards