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4.8.1 Kinematics (A-level only)

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How is displacement found from initial and final position vectors?

A

Displacement is s=r−r0\mathbf{s}=\mathbf{r}-\mathbf{r}_0s=r−r0​.

B

v=(12−14) m s−1\mathbf{v}=\begin{pmatrix}12\\-14\end{pmatrix}\text{ m s}^{-1}v=(12−14​) m s−1.

C

For an ideal projectile, the velocity components are vx=uxv_x=u_xvx​=ux​ and vy=uy−gt\boxed{v_y=u_y-gt}vy​=uy​−gt​.

D

v=(70) m s−1\mathbf{v}=\begin{pmatrix}7\\0\end{pmatrix}\text{ m s}^{-1}v=(70​) m s−1.

Card 1 of 24

4.8.1 Kinematics (A-level only) Flashcards

  1. A Level
  2. /Maths
  3. /4.8.1 Kinematics (A-level only)

24 flashcards on WJEC A Level Maths 4.8.1 Kinematics (A-level only): the key formulae, methods and definitions you need to recall for AS Unit 1, AS Unit 2, A2 Unit 3 and A2 Unit 4.

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