A marine biologist models the rate of change of nutrient density DDD with respect to the depth hhh (in meters) of a water column as:
dDdh=7h5−414h6,h>0 \frac{dD}{dh} = \frac{7h^5 - 4}{14h^6}, \quad h > 0 dhdD=14h67h5−4,h>0Find an expression for DDD in terms of hhh, giving your answer in its simplest form.
160 exam-style questions on WJEC A Level Maths 1.8 Integration, covering 1.8.1 Integration, 1.8.2 Integration, and 1.8.3 Integration. Each one has a worked solution and a mark scheme showing where the marks go.