A scientist monitoring the growth of a synthetic crystal determines that the rate of change of its mass, MMM in milligrams, with respect to time ttt in hours, is given by:
dMdt=5t4−3t34,t>0 \frac{dM}{dt} = 5t^4 - \frac{3}{\sqrt[4]{t^3}}, \quad t > 0 dtdM=5t4−4t33,t>0Determine the general expression for the mass M(t)M(t)M(t).
160 exam-style questions on WJEC A Level Maths 1.8 Integration, covering 1.8.1 Integration, 1.8.2 Integration, and 1.8.3 Integration. Each one has a worked solution and a mark scheme showing where the marks go.