Use the substitution x=3sinux = 3 \sin ux=3sinu to evaluate ∫01.539−x2dx\displaystyle \int_0^{1.5} \frac{3}{\sqrt{9-x^2}} dx∫01.59−x23dx
111 exam-style questions on WJEC A Level Maths 3.7.4 Integration (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.