Use the substitution x=sinux = \sin ux=sinu to find ∫02211−x2dx\displaystyle \int_0^{\frac{\sqrt{2}}{2}} \frac{1}{\sqrt{1-x^2}} dx∫0221−x21dx
111 exam-style questions on WJEC A Level Maths 3.7.4 Integration (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.