Find: ∫12cos2(4x−5) dx\displaystyle \int \frac{1}{2 \cos^2(4x-5)} \, dx∫2cos2(4x−5)1dx
Find: ∫(tanα−secα)2 dα\int (\tan \alpha - \sec \alpha)^2 \, d\alpha∫(tanα−secα)2dα