The curve C C\,C has equation y=f(x)y = f(x)y=f(x) where x>0x > 0x>0.
Given that
(i) Find the value of the gradient of the curve at PPP.
(ii) Hence find the equation of the tangent to C C\,C at PPP, giving your answer in the form ax+by+c=0ax + by + c = 0ax+by+c=0, where aaa, b b\,b and c c\,c are integers to be found.
Find f(x)f(x)f(x), simplifying your answer.