Find the exact value of ∫244x2−3x+5(x−1)2(x+2)dx\displaystyle \int_2^4 \frac{4x^2 - 3x + 5}{(x-1)^2(x+2)} dx∫24(x−1)2(x+2)4x2−3x+5dx
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Markscheme
3.7.5 Integration (A-level only) Questions
19 exam-style questions on WJEC A Level Maths 3.7.5 Integration (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.