In this question use g=9.8g = 9.8g=9.8 m s−2^{-2}−2
A man of mass 70 kg stands on the floor of a lift.
The lift is moving vertically upwards with acceleration 1.5 m s−2^{-2}−2.
Find the magnitude of the normal reaction force exerted by the floor of the lift on the man.
State the magnitude and direction of the force exerted by the man on the floor of the lift, giving a reason for your answer.
35 exam-style questions on WJEC A Level Maths 2.8 Forces and Newton's laws, covering 2.8.1 Forces and Newton's laws, 2.8.2 Forces and Newton's laws, 2.8.3 Forces and Newton's laws, 2.8.4 Forces and Newton's laws, 2.8.5 Forces and Newton's laws, and 2.8.6 Forces and Newton's laws. Each one has a worked solution and a mark scheme showing where the marks go.