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Card 1 of 24

For the same base, am⋅an=a^m\cdot a^n=am⋅an= [...]\text{[...]}[...].

A

am−na^{m-n}am−n

B

−3-3−3

C

For the same base, am⋅an=a^m\cdot a^n=am⋅an= am+n\boxed{a^{m+n}}am+n​.

D

log⁡2(18)=−3\log_2\left(\dfrac{1}{8}\right)=-3log2​(81​)=−3

Card 1 of 24

1.6.4 Exponentials and logarithms Flashcards

  1. A Level
  2. /Maths
  3. /1.6.4 Exponentials and logarithms

24 flashcards on WJEC A Level Maths 1.6.4 Exponentials and logarithms: the key formulae, methods and definitions you need to recall for AS Unit 1, AS Unit 2, A2 Unit 3 and A2 Unit 4.

Flashcards