A curve has equation
y=2x3−3x2−12x+7 y = 2x^3 - 3x^2 - 12x + 7 y=2x3−3x2−12x+7Using calculus, find the xxx-coordinates of the stationary points of the curve.
Justify, by further calculus, the nature of each stationary point.
333 exam-style questions on WJEC A Level Maths 3.6 Differentiation (A-level only), covering 3.6.1 Differentiation (A-level only), 3.6.2 Differentiation (A-level only), 3.6.3 Differentiation (A-level only), 3.6.4 Differentiation (A-level only), 3.6.5 Differentiation (A-level only), 3.6.6 Differentiation (A-level only), 3.6.7 Differentiation (A-level only), and 3.6 Differentiation (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.