The point P P\,P lies on the curve with equation y=sec(x2)\displaystyle y = \sec \left( \frac{x}{2} \right)y=sec(2x) with x x\,x coordinate 2π3\displaystyle \frac{2\pi}{3}32π.
Find an equation of the normal to the curve at the point PPP.
133 exam-style questions on WJEC A Level Maths 3.6.5 Differentiation (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.