A signal processing algorithm converts an input voltage vvv into a compressed metric M(v)M(v)M(v) using the formula:
M(v)=ev/4+10 M(v) = e^{v/4} + 10 M(v)=ev/4+10for v∈Rv \in \mathbb{R}v∈R.
Identify the expression for the inverse function M−1(x)M^{-1}(x)M−1(x).
Tick (✓\checkmark✓) one box.
□M−1(x)=4ln(x)−10\square \quad M^{-1}(x) = 4\ln(x) - 10□M−1(x)=4ln(x)−10
□M−1(x)=1ex/4+10\square \quad M^{-1}(x) = \frac{1}{e^{x/4} + 10}□M−1(x)=ex/4+101
□M−1(x)=4ln(x−10)\square \quad M^{-1}(x) = 4\ln(x - 10)□M−1(x)=4ln(x−10)
□M−1(x)=ln(x−10)+4\square \quad M^{-1}(x) = \ln(x - 10) + 4□M−1(x)=ln(x−10)+4
216 exam-style questions on WJEC A Level Maths 3.2 Algebra and Functions (A-level only), covering 3.2.1 Algebra and Functions (A-level only), 3.2.2 Algebra and Functions (A-level only), 3.2.3 Algebra and Functions (A-level only), 3.2.4 Algebra and Functions (A-level only), 3.2.5 Algebra and Functions (A-level only), 3.2.6 Algebra and Functions (A-level only), and 3.2 Algebra and Functions (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.