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1.5 Trigonometry

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Question 49

In the analysis of a resonant electronic circuit, the phase shift α \alpha\,α across a specific component is related to the impedance through a series of trigonometric relationships.

a.

Prove that

cot⁡α−tan⁡α≡2cot⁡2α \cot \alpha - \tan \alpha \equiv 2 \cot 2\alpha cotα−tanα≡2cot2α

for α≠nπ2,n∈Z\displaystyle \alpha \neq \frac{n\pi}{2}, n \in \mathbb{Z}α=2nπ​,n∈Z.

[3]
b.

Using the identity in part (a), or otherwise, establish that

cot⁡2α−tan⁡2α≡4cot⁡2αcsc⁡2α \cot^2 \alpha - \tan^2 \alpha \equiv 4 \cot 2\alpha \csc 2\alpha cot2α−tan2α≡4cot2αcsc2α
[3]
c.

A particular resonance condition occurs when the operating phase ϕ \phi\,ϕ satisfies the equation

4cot⁡2ϕcsc⁡2ϕ=15tan⁡2ϕ 4 \cot 2\phi \csc 2\phi = 15 \tan^2 \phi 4cot2ϕcsc2ϕ=15tan2ϕ

Solve this equation for −π2<ϕ<π2\displaystyle -\frac{\pi}{2} < \phi < \frac{\pi}{2}−2π​<ϕ<2π​, giving your answers to 2 decimal places.

[4]
Markscheme

1.5 Trigonometry Questions

  1. A Level
  2. /Maths
  3. /1.5 Trigonometry

317 exam-style questions on OCR A Level Maths 1.5 Trigonometry, covering 1.5.1 Definitions for all arguments, 1.5.2 Sine and cosine rules, 1.5.3 Area of a triangle, 1.5.4 Radian measure (A-level only), 1.5.5 Small angle approximations (A-level only), 1.5.6 Graphs of basic trigonometric functions, 1.5.7 Exact values in radians (A-level only), 1.5.8 Reciprocal and inverse trigonometric ratios (A-level only), 1.5.9 Graphs of reciprocal and inverse functions (A-level only), 1.5.10 Trigonometric identities, 1.5.11 Further trigonometric identities (A-level only), 1.5.12 Double angle and compound angle formulae (A-level only), 1.5.13 Geometrical proofs of formulae (A-level only), 1.5.14 Harmonic form Rcos / Rsin (A-level only), 1.5.15 Trigonometric equations, 1.5.16 Proof involving trigonometric functions (A-level only), and 1.5.17 Trigonometric functions in context. Each one has a worked solution and a mark scheme showing where the marks go.

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