Question 35
Figure 1 below shows the sector AOB AOB\,AOB of a circle.
A student's attempt to find the area of the sector AOB AOB\,AOB is shown below.
Area =12r2θ=12×62×40=720\displaystyle = \frac{1}{2}r^2\theta = \frac{1}{2} \times 6^2 \times 40 = 720=21r2θ=21×62×40=720 cm2^22
a.[1]
Identify the mistake made by the student.
b.[2]
Write out a correct solution.
1.5 Trigonometry Questions
317 exam-style questions on OCR A Level Maths 1.5 Trigonometry, covering 1.5.1 Definitions for all arguments, 1.5.2 Sine and cosine rules, 1.5.3 Area of a triangle, 1.5.4 Radian measure (A-level only), 1.5.5 Small angle approximations (A-level only), 1.5.6 Graphs of basic trigonometric functions, 1.5.7 Exact values in radians (A-level only), 1.5.8 Reciprocal and inverse trigonometric ratios (A-level only), 1.5.9 Graphs of reciprocal and inverse functions (A-level only), 1.5.10 Trigonometric identities, 1.5.11 Further trigonometric identities (A-level only), 1.5.12 Double angle and compound angle formulae (A-level only), 1.5.13 Geometrical proofs of formulae (A-level only), 1.5.14 Harmonic form Rcos / Rsin (A-level only), 1.5.15 Trigonometric equations, 1.5.16 Proof involving trigonometric functions (A-level only), and 1.5.17 Trigonometric functions in context. Each one has a worked solution and a mark scheme showing where the marks go.