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1.5.8 Reciprocal and inverse trigonometric ratios (A-level only)

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Question 13

Solve, for 0≤x≤3600 \leq x \leq 3600≤x≤360, the equation,

2tan⁡2x+7sec⁡x+1=0 2\tan^2x + 7\sec x + 1 = 0 2tan2x+7secx+1=0

Give your answers to 1 decimal place.

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1.5.8 Reciprocal and inverse trigonometric ratios (A-level only) Questions

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  3. /1.5.8 Reciprocal and inverse trigonometric ratios (A-level only)