Use the identity cos2θ+sin2θ≡1\cos^2\theta + \sin^2\theta \equiv 1cos2θ+sin2θ≡1 to prove that cosec2θ≡1+cot2θ\operatorname{cosec}^2\theta \equiv 1 + \cot^2\thetacosec2θ≡1+cot2θ.
Solve, for 0≤θ≤2π0 \leq \theta \leq 2\pi0≤θ≤2π, the equation
cosec2θ+cot2θ=3\operatorname{cosec}^2\theta + \cot^2\theta = 3cosec2θ+cot2θ=3
Give your answers in terms of π\piπ.