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1 Pure Mathematics

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Question 362

A curve has equation y=e2xy = e^{2x}y=e2x

a.

Find, in terms of aaa, the equation of the tangent to the curve at the point (a, e2a)\left(a,\, e^{2a}\right)(a,e2a).

[3]
b.

Find the value of a a\,a for which this tangent passes through the origin.

[2]
c.

Hence find the set of values of m m\,m for which the equation e2x=mxe^{2x} = mxe2x=mx has no real solutions.

[3]
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1 Pure Mathematics Questions

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