An arithmetic series is given by

$∑n=1150(bn+c)\sum_{n=11}^{50} (bn + c)$

where $b\,$ and $c\,$ are constants. The sum of the series is 2680.

Show that $61 b + 2 c = 134$ .

Given that the 21st term of the sequence $u_n = bn + c$ is 4 times its 3rd term, find the value of $b\,$ and the value of $c$ .

An arithmetic series is given by

$∑n=1150(bn+c)\sum_{n=11}^{50} (bn + c)$

where $b\,$ and $c\,$ are constants. The sum of the series is 2680.

Show that $61 b + 2 c = 134$ .

Given that the 21st term of the sequence $u_n = bn + c$ is 4 times its 3rd term, find the value of $b\,$ and the value of $c$ .

1 Pure Mathematics

1 Pure Mathematics Questions