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1 Pure Mathematics

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Question 137

Use the substitution u=x3−4u = x^3 - 4u=x3−4 to find the exact value of

∫232x2(x3−4)2 dx\displaystyle\int_2^3 2x^2\left(x^3 - 4\right)^2\,dx∫23​2x2(x3−4)2dx

[6]
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