In this question you must show detailed reasoning.
The function f f\,f is defined by f(x)=x+1(x−1)(x−2)\displaystyle f(x)=\frac{x+1}{(x-1)(x-2)}f(x)=(x−1)(x−2)x+1, where x≠1 x\ne1\,x=1 and x≠2x\ne2x=2.
Express f(x)f(x)f(x) in partial fractions.
Show that, for a constant kkk, the equation f(x)=kf(x)=kf(x)=k can be written as kx2−(3k+1)x+2k−1=0kx^2-(3k+1)x+2k-1=0kx2−(3k+1)x+2k−1=0.
Determine the values of k k\,k for which the equation f(x)=kf(x)=kf(x)=k has exactly one real solution.