You are given that
(1+x)−12=1−12x+38x2−516x3+⋯\displaystyle (1+x)^{-\frac12}=1-\frac12x+\frac38x^2-\frac5{16}x^3+\cdots(1+x)−21=1−21x+83x2−165x3+⋯.
Find the expansion of 1+2x1+x\dfrac{1+2x}{\sqrt{1+x}}1+x1+2x up to and including the term in x3x^3x3.