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1 Pure Mathematics

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Question 72

Find the equation of the normal to the curve y=(4x−1)(x+2)2xy = \dfrac{(4x - 1)(x + 2)}{2x}y=2x(4x−1)(x+2)​ at the point where x=−2x = -2x=−2.

Give your answer in the form ax+by+c=0ax + by + c = 0ax+by+c=0, where aaa, b b\,b and c c\,c are integers.

[6]
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1 Pure Mathematics Questions

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