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1 Pure Mathematics

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Question 67

It is given that θ \theta\,θ satisfies the equation

sin⁡(2θ−45°)=3cos⁡(2θ−45°)\sin(2\theta - 45°) = 3\cos(2\theta - 45°)sin(2θ−45°)=3cos(2θ−45°)

a.

Show that tan⁡2θ=−2\tan 2\theta = -2tan2θ=−2.

[3]
b.

Hence find, in surd form, the exact value of tan⁡θ\tan\thetatanθ, given that θ \theta\,θ is an obtuse angle.

[5]
Markscheme

1 Pure Mathematics Questions

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