Use the derivatives of sinx \sin x\,sinx and cosx\cos xcosx, where x x\,x is measured in radians, to show that
ddx(tanx)=sec2x\dfrac{d}{dx}(\tan x) = \sec^2 xdxd(tanx)=sec2x
ddx(secx)=secxtanx\dfrac{d}{dx}(\sec x) = \sec x\tan xdxd(secx)=secxtanx