The acoustic power PPP of a specialized sonar pulse is modeled as a function of its frequency fff (in kHz) by the equation
P(f)=f−10e0.05f+4,f>0 P(f) = f^{-10} e^{0.05f + 4}, \quad f > 0 P(f)=f−10e0.05f+4,f>0Show that the power PPP has exactly one stationary point. Fully justify your answer.