A scientist is studying the potential of a chemical reaction, modeled by the equation
V=kt+12 V = k^t + 12 V=kt+12where kkk is a constant such that k>1k > 1k>1 and ttt is time. Sketch the graph of VVV against ttt.
On your sketch, show:
| ttt | 0 | 0.5 | 1 | 1.5 | 2 |
|---|---|---|---|---|---|
| R(t)R(t)R(t) | -3 | -2.2679 | -1 | 1.1962 | 5 |
The table shows corresponding values of time ttt and the rate of airflow R(t)R(t)R(t) in a ventilation shaft, where
R(t)=3t−4 R(t) = 3^t - 4 R(t)=3t−4Using the trapezium rule with all the values of R(t)R(t)R(t) in the given table, obtain an estimate for
∫02(3t−4) dt \int_{0}^{2} (3^t - 4) \, dt ∫02(3t−4)dtgiving your answer to 2 decimal places.
Using your answer to part (b) and making your method clear, estimate
(i)
∫02(3t+2) dt \int_{0}^{2} (3^t + 2) \, dt ∫02(3t+2)dt(ii)
∫02(3t+1−12) dt \int_{0}^{2} (3^{t+1} - 12) \, dt ∫02(3t+1−12)dt