A particle moves in a straight line with acceleration a=(3t+5) m s−2a=(3t+5)\text{ m s}^{-2}a=(3t+5) m s−2. At t=0t=0t=0 its velocity is 2 m s-1. At time t=Tt=Tt=T, its velocity is 6 m s-1.
Show that 3T2+10T−8=03T^2+10T-8=03T2+10T−8=0.
Determine TTT.
Find the distance travelled between t=0t=0t=0 and t=Tt=Tt=T.
46 exam-style questions on OCR A Level Maths 3.2.6 Non-uniform acceleration in one dimension (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.