Card 1 of 21
With upward positive, what is the acceleration vector under gravity?
A
a=(0−g)\mathbf{a}=\begin{pmatrix}0\\-g\end{pmatrix}a=(0−g), where g=9.8 m s−2g=9.8\text{ m s}^{-2}g=9.8 m s−2.
B
Substitute the same ttt into the horizontal position equation.
C
The particle is moving downwards.
D
When launch and landing are at different vertical levels.
Card 1 of 21
3.2.8 Motion under gravity using vectors (A-level only) Flashcards
21 flashcards on OCR A Level Maths 3.2.8 Motion under gravity using vectors (A-level only): the key formulae, methods and definitions you need to recall for Paper 1, Paper 2 and Paper 3.