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1.7 Trigonometry

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Question 88
a.

Solve the equation sin⁡2x=0.25\sin^2 x = 0.25sin2x=0.25 for 0∘≤x<360∘0^\circ \leq x < 360^\circ0∘≤x<360∘

[3]
b.

Solve the equation tan⁡3x=1\tan 3x = 1tan3x=1 for 0∘≤x<180∘0^\circ \leq x < 180^\circ0∘≤x<180∘

[3]

1.7 Trigonometry Questions

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