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1.7 Trigonometry

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Question 16

Solve, for 0≤x≤3600 \leq x \leq 3600≤x≤360, the equation,

3tan⁡2x+8sec⁡x−2=0 3\tan^2x + 8\sec x - 2 = 0 3tan2x+8secx−2=0

Give your answers to 1 decimal place.

[5]

1.7 Trigonometry Questions

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