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1.7 Trigonometry

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Question 14
a.

Use the identity cos⁡2θ+sin⁡2θ=1\cos^2\theta + \sin^2\theta = 1cos2θ+sin2θ=1 to prove that sec⁡2θ=1+tan⁡2θ\sec^2\theta = 1 + \tan^2\thetasec2θ=1+tan2θ

[2]
b.

Solve, for 0≤θ≤3600 \leq \theta \leq 3600≤θ≤360, the equation,

3tan⁡2θ+5sec⁡θ+1=0 3\tan^2\theta + 5\sec\theta + 1 = 0 3tan2θ+5secθ+1=0

Give your answers to 1 decimal place.

[5]

1.7 Trigonometry Questions

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