Events A A\,A and B B\,B are independent. It is given that P(A)=pP(A)=pP(A)=p, P(B)=p+0.20P(B)=p+0.20P(B)=p+0.20 and the probability that neither event occurs is 0.24.
Show that p p\,p satisfies p2−1.8p+0.56=0p^2-1.8p+0.56=0p2−1.8p+0.56=0.
Find ppp, explaining why one algebraic solution is rejected.
Find the probability that both A A\,A and B B\,B occur.