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2.5 Statistical Hypothesis Testing

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Question 78

The concentration of a particular catalyst in a chemical batch is modelled by a normal distribution with an unknown mean μ \mu\,μ mg/L and a known standard deviation σ \sigma\,σ mg/L.

A random sample of 80 batches was analysed, resulting in a 98% confidence interval for μ \mu\,μ of (12.42,13.58)(12.42, 13.58)(12.42,13.58).

a.

Using this confidence interval, conduct a hypothesis test to determine whether μ=12.5\mu = 12.5μ=12.5. State your null and alternative hypotheses, the significance level used, and your conclusion.

[3]
b.

A second random sample of 150 batches is taken, and the mean concentration is found to be 13.2 mg/L.

Calculate a 90% confidence interval for μ \mu\,μ based on this second sample. Show your intermediate calculations, including the value of σ \sigma\,σ derived from the first sample.

[6]
c.

Eight independent random samples, each consisting of 150 batches, are used to construct eight separate 90% confidence intervals for μ\muμ.

Calculate the probability that at least 7 of these 8 intervals will contain the true population mean μ\muμ.

[4]
Markscheme

2.5 Statistical Hypothesis Testing Questions

  1. A Level
  2. /Maths
  3. /2.5 Statistical Hypothesis Testing

355 exam-style questions on OCR (MEI) A Level Maths 2.5 Statistical Hypothesis Testing, covering 2.5.1 Process and language of hypothesis testing, 2.5.2 When to apply 1-tail and 2-tail tests, 2.5.3 Significance level and incorrect rejection, 2.5.4 Null and alternative hypotheses (binomial), 2.5.5 Conduct a binomial hypothesis test, 2.5.6 Critical and acceptance regions (binomial), 2.5.7 Distribution of the sample mean (A-level only), 2.5.8 Hypothesis test for a single mean (A-level only), 2.5.9 Critical and acceptance regions (mean) (A-level only), 2.5.10 Correlation as closeness to a straight line (A-level only), 2.5.11 Inference using a correlation coefficient (A-level only), and 2.5 Statistical Hypothesis Testing. Each one has a worked solution and a mark scheme showing where the marks go.

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