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1.6.15 Standard formulae for geometric series (A-level only)

1.6.15 Standard formulae for geometric series (A-level only)

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Question 7

A geometric progression has first term u1 u_1\,u1​ and common ratio kkk.

Show that the sum of the first n n\,n terms of this progression, SnS_nSn​, can be expressed as

Sn=u1(1−kn)1−k S_n = \frac{u_1(1 - k^n)}{1 - k} Sn​=1−ku1​(1−kn)​
[4]
Markscheme

1.6.15 Standard formulae for geometric series (A-level only) Questions

  1. A Level
  2. /Maths
  3. /1.6.15 Standard formulae for geometric series (A-level only)

22 exam-style questions on OCR (MEI) A Level Maths 1.6.15 Standard formulae for geometric series (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.

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