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In the projectile model, horizontal acceleration is [...]\text{[...]}[...] and vertical acceleration is −g-g−g when upward is positive.
For launch speed uuu at angle θ\thetaθ above the horizontal, ux=u_x=ux= ucosθu\cos\thetaucosθ and uy=u_y=uy= usinθ\boxed{u\sin\theta}usinθ.
In the projectile model, horizontal acceleration is 0\boxed{0}0 and vertical acceleration is −g-g−g when upward is positive.
For launch speed uuu at angle θ\thetaθ above the horizontal, ux=u_x=ux= ucosθ\boxed{u\cos\theta}ucosθ and uy=u_y=uy= usinθu\sin\thetausinθ.
v=v=v= vx2+vy2\sqrt{v_x^2+v_y^2}vx2+vy2.
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3.3.5 Solve simple projectile problems (A-level only) Flashcards
22 flashcards on OCR (MEI) A Level Maths 3.3.5 Solve simple projectile problems (A-level only): the key formulae, methods and definitions you need to recall for Component 01, Component 02 and Component 03.