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2.4 Probability Distributions

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Question 39

The lifespan, T T\,T hours, of a certain component is normally distributed. Given that P(T<800)=0.3P(T < 800) = 0.3P(T<800)=0.3 and P(T>1200)=0.15P(T > 1200) = 0.15P(T>1200)=0.15.

Find the mean and standard deviation of the lifespan of the component.

[6]

2.4 Probability Distributions Questions

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